{"id":3869689,"date":"2021-10-03T20:03:02","date_gmt":"2021-10-03T18:03:02","guid":{"rendered":"https:\/\/doir.hu\/termek\/20-db-csere-az-irobot-roomba-porszivo-alkatreszeihez-tartozekok-fokefek4-oldalkefek6-heap-szurok4-csavarok6-nem-eredeti\/"},"modified":"2022-05-02T13:53:07","modified_gmt":"2022-05-02T11:53:07","slug":"20-db-csere-az-irobot-roomba-porszivo-alkatreszeihez-tartozekok-fokefek4-oldalkefek6-heap-szurok4-csavarok6-nem-eredeti","status":"publish","type":"product","link":"https:\/\/doir.hu\/termek\/20-db-csere-az-irobot-roomba-porszivo-alkatreszeihez-tartozekok-fokefek4-oldalkefek6-heap-szurok4-csavarok6-nem-eredeti\/","title":{"rendered":"20 db csere az iRobot Roomba porsz\u00edv\u00f3 alkatr\u00e9szeihez Tartoz\u00e9kok F\u0151kef\u00e9k*4 Oldalkef\u00e9k*6 HEAP sz\u0171r\u0151k*4 Csavarok*6 [Nem eredeti]"},"content":{"rendered":"
\n term\u00e9kle\u00edr\u00e1s<\/font><\/p>\n<\/th>\n | 20 db Csere az iRobot Roomba porsz\u00edv\u00f3 alkatr\u00e9szeihez Tartoz\u00e9kok F\u0151kef\u00e9k*4 Oldalkef\u00e9k*6 HEAP sz\u0171r\u0151k*4 Csavarok*6<\/font> <\/font><\/p>\n Kompatibilis az al\u00e1bbiakkal: i<\/font>Robot Roomba porsz\u00edv\u00f3<\/font><\/div>\n<\/td>\n<\/tr>\n Jellemz\u0151k<\/font><\/th>\n | \n | \u25cf <\/span><\/font>J\u00f3 min\u0151s\u00e9g.<\/font><\/div>\n \u25cf <\/span><\/font>Kiv\u00e1l\u00f3 min\u0151s\u00e9g\u0171 anyagokb\u00f3l k\u00e9sz\u00fclt, tart\u00f3sabb.<\/font><\/div>\n \u25cf <\/span><\/font>Kiv\u00e1l\u00f3 \u00e9s finom, nagyon illeszkedik az eredeti felszerel\u00e9shez.<\/font><\/div>\n \u25cf <\/span><\/font>Szil\u00e1rd \u00e9s tart\u00f3s, hossz\u00fa \u00e9lettartam.<\/font><\/div>\n \u25cf <\/span><\/font>A norm\u00e1l karbantart\u00e1s r\u00e9szek\u00e9nt k\u00f6nnyen elt\u00e1vol\u00edthat\u00f3 \u00e9s cser\u00e9lhet\u0151.<\/font><\/div>\n \u25cf <\/span><\/font>A legjobb, ha a p\u00f3talkatr\u00e9szeket 2-3 havonta cser\u00e9li, hogy a g\u00e9p m\u0171k\u00f6d\u0151k\u00e9pes maradjon.<\/font><\/div>\n<\/td>\n<\/tr>\n \n | Le\u00edr\u00e1s<\/font><\/p>\n<\/th>\n \n |
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